0.2x+0.3y=1.3
o. 4x+0.5y=2.3
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0.2x+0.3y=1.3---------------(1)
0.4x+0.5y=2.3-------------(2)
equation (1)*2=0.4x+0.6y=2.6
equation (2)*1=0.4x+0.5y=2.3
substraction equation (1)and(2)
=>0.1y=0.3
=>y=0.3/0.1=3
substitute the value of y in equation (1)
0.2x+0.3(3)=1.3
=>0.2x+0.9=1.3
=>0.2x=0.4
=>x=0.4/0.2=2
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0.4x+0.5y=2.3-------------(2)
equation (1)*2=0.4x+0.6y=2.6
equation (2)*1=0.4x+0.5y=2.3
substraction equation (1)and(2)
=>0.1y=0.3
=>y=0.3/0.1=3
substitute the value of y in equation (1)
0.2x+0.3(3)=1.3
=>0.2x+0.9=1.3
=>0.2x=0.4
=>x=0.4/0.2=2
I think this will help you
please mark me as a Breanlist
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