Question

0.2x+0.3y=13 0.4x+0.5y=2.3 by using substitution method

Answer 1

0.2x+0.3y=13 => 2x+3y=130=> x=(130-3y)/2
0.4x+0.5y=2.3 => 4x+3y=23
putting x in terms of y we get
$4 \times \frac{130 - 3y}{2} + 3y = 23 \\ 2(130 - 3y) + 3y = 23 \\ 260 - 6y + 3y = 23 \\ - 6y + 3y = 23 - 260 \\ - 3y = - 237 \\ y = \frac{ - 237}{ - 3} = 79$
$x = \frac{130 - 3(79)}{2} \\ x = \frac{130 - 237}{2} \\ x = \frac{ - 107}{2}$

Answer 2

Answer:

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