Question

0 (2x-1) (x-3) = (x+5)(x-1)​

Answer 1

Answer:

2x – 1) (x – 3) = (x + 5) (x – 1)

We have:

(2x – 1) (x – 3) = (x + 5) (x – 1)

⇒ 2x2 – 6x – x + 3 = x2 – x + 5x – 5

⇒ 2x2 – x2 – 6x – x + x – 5x + 3 + 5 = 0

⇒ x2 – 11x + 8 = 0

Since x2 – 11x + 8 is a quadratic polynomial

∴ (2x – 1) (x – 3) = (x + 5) (x – 1) is a quadratic equation.