Math, asked by mrunalikhairkar40, 7 months ago

0.3+0.33+0.333+0.3333+..........15 th term

Answers

Answered by Anonymous

1

Answer:

3[0.1+0.11+0.111....0.111(ntimes)]

39[0.9+0.99+0.999....0.999((ntimes)]

39[(1+1+1...)−(0.1+0.01....)]

39[(n)−1/10(1−1/10n)9/10]

39[(n)−1−1/10n9]

39[9n−1+1/10n9]

9n−1+1/10n27

Step-by-step explanation:

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