Question

0.3 +0.33 +0.333…............ n पदो का योग

Answer 1

Answer:

0.3+0.03+0.003+...=13

Explanation:

The sum of a geometric series with initial term aand common ratio r where |r|<1 is given by

∞∑n=0arn=a1−r

(A derivation of this result is included in this answer)

Applying this to the given series, we get

0.3+0.03+0.003+...=∞∑n=0310(110)n

=3101−110

=310910

=13

Note that this result intuitively makes sense just looking at the series, as

0.3+0.03+0.003+...=0.¯3=13