Question

0.3
3. Derive
an expression for minimum safest
velocity of a body to move in well of death.

​

Answer 1

Answer:

When the motorcyclist is at the highest point of the death - well, the normal reaction R on the motorcyclist by the ceiling of the chamber acts downwards. His weight mg also act downwards.

F

net

=ma

c

⇒R+mg=

r

mv

2

Here v is the speed of the motorcyclist and m is the mass of does not fall down. The minimum speed required to perform a vertical loop is given by equation (1) when R=0.

Therefore,

mg=

r

mv

min

2

orv

min

2

=grorv

min

=

gr

=

9.8×25m/s

=15.65m/s.

So, the minimum speed, at the top, required to perform a vertical loop is 15.65 m/s.