Question

0.3 A liquid of mass M and specific heat S is at temperature 21. If another liquid of thermal capacity
1.5 times at a temperature of t/3 is added to it, the resultant temperature will be​

Answer 1

Answer:

12.6

Explanation:

Let the final temperature be T

therefore since heat gained= heat lost;

MS(21-T)=M(1.5S)(T-7)

63=5T

Therefore T=12.6

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