0.3 A liquid of mass M and specific heat S is at temperature 21. If another liquid of thermal capacity
1.5 times at a temperature of t/3 is added to it, the resultant temperature will be
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Answer:
12.6
Explanation:
Let the final temperature be T
therefore since heat gained= heat lost;
MS(21-T)=M(1.5S)(T-7)
63=5T
Therefore T=12.6
Hope this helps you :)
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