Question

0.3. ABCD is a trapezium in which AB = 7 cm, AD = BC = 5 cm.
Distance between AB and DC is 4 cm find length DC.​

Answer 1

Answer:

AB = 7 of the 2 triangle formed

Leff and right Base=v5^2-4^2 = 3

3 each

so DC=7-2x3=1

DC=1 cm. Ans