Question

0/3. Find the LCM and HCF of the following integers by applying the prime factorisation
method.
06) 12,15 and 21
​

Answer 1

Answer:

Hcf=3& Lcm=420

Step-by-step explanation:

12=(2)(2)(3)

15=(3)(5)

21=(3)(7)

Hcf=3

Lcm=(2)(2)(3)(5)(7)=420

Answer 2

:

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Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800