Question

0.3 g of an oxalate salt was dissolved in 100 ml solution. The solution required 90 mL of N/20 KMnO, for
complete oxidation. The % of oxalate ion in salt is
(D)40%
(C) 70%
(B) 66%
(A) 33%​

Answer 1

Answer:

Explanation:

Given 0.3 g of an oxalate salt was dissolved in 100 ml solution. The solution required 90 mL of N/20 KMnO, for  complete oxidation. The % of oxalate ion in salt is

Given Milli equivalent of oxalate ion is equal to Milli equivalent of KMnO4

w/E x 1000 – 90 x 1/20

w/E x 1000 = 90/20

We know that E c2o4^2 = 88/2 = 44

So w/E x 1000 = 90 / 20

 W = 90/20 x 44/1000

  W = 0.198

Since 0.3 g of oxalate sample has 0.198 g of oxalate ion.

Therefore percentage of oxalate in sample will be = 0.198 x 100 / 0.3

        = 19.8 / 0.3

        = 66%

The % of oxalate ion in salt is  66%