0.3. If one of the zeroes of the cubic polynomial
x3 + ax² + bx + c is –1, then the product of the
other two zeroes is :
(a) b-a + 1
(b) b-a-1
(c) a – b + 1
(d) a - b - 1
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Answer:
option a )
put x= -1
get the value of c
aby = c/1
a=-1
get the value of by.
GO THROUGH THE PROCESS YOU WILL GET THE ANSWER.
I hope it will help you...
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