0.3 kg of steam at 100°c is mixed with 6 kg of water. After the steam condenses the temperature of the mixture rises to 40°c. The initial temperature of the water is
Answers
Answered by
1
Explanation:
Heat released by steam on condesation is Q
1
=0.3×2260×10
3
J ;
where, Latent heat of condensation of steam is : 2260×10
3
J/kg
o
C
Let the initial temperature of water be T.
Balancing the energy released and absorbed,
Q
1
+0.3×4200×(100−40)=6×4200×(40−T) ;
where spceific heat of water is: 4200 J/kg
o
C
So, 40−T≈30⇒T=10
o
Answered by
0
Answer:
the initial temperature of water is 80°c
Similar questions