Physics, asked by sheikhsanasadiya, 20 days ago

0.3 kg of steam at 100°c is mixed with 6 kg of water. After the steam condenses the temperature of the mixture rises to 40°c. The initial temperature of the water is​

Answers

Answered by shakshi88
1

Explanation:

Heat released by steam on condesation is Q

1

=0.3×2260×10

3

J ;

where, Latent heat of condensation of steam is : 2260×10

3

J/kg

o

C

Let the initial temperature of water be T.

Balancing the energy released and absorbed,

Q

1

+0.3×4200×(100−40)=6×4200×(40−T) ;

where spceific heat of water is: 4200 J/kg

o

C

So, 40−T≈30⇒T=10

o

Answered by yaumm623
0

Answer:

the initial temperature of water is 80°c

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