0.3. Short answer type question
1.
Find the height of the parallelogram if its area is 246 cm' and base is 20cm,
Draw a rough sketch of ADEF. Which angle is included between DE and EP of ADEF.
2.
3.
Find the value of unknown exterior angle x in the given figure
50
X
700
Answers
Answer:
3)
Find the value of unknown exterior angle x in the given figure 50 X 700
Answere :
∠A + ∠B+ ∠C = 180° { angle sum property of triangle }
70\degree+\ 50\degree+\ \angle B\ =\ 180\degree70°+ 50°+ ∠B = 180°
\angle B\ =\ 180\degree-\ 120\degree∠B = 180°− 120°
\angle B\ =\ 60\degree∠B = 60°
(ii) \angle BAC\ +\angle ACB\ =\ x\∠BAC +∠ACB = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }
65\degree+45\degree=x65°+45°=x
110\degree=x110°=x
(iii) \angle CAB+\angle ABC\ =\ x∠CAB+∠ABC = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }
30\degree+40\degree\ =\ x\30°+40° = x
70\degree=x70°=x
(iv) \angle BCA+\angle CBA\ =\ x∠BCA+∠CBA = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }
60\degree+60\degree\ =\ x60°+60° = x
120\degree=x120°=x
(v) \angle A+\angle B=\ x∠A+∠B= x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }
50\degree+50\degree=\ x50°+50°= x
100\degree=\ x\100°= x
(vi) \angle A+\angle B\ =\ x\∠A+∠B = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }
30\degree+60\degree\ =\ x\30°+60° = x
90\degree=\ x90°= x
Answer = Area = 246 cm
base = 20 cm
Area of parallogram = 1/2×b×h
246 cm = 1/2×20×h
H = 24.6 cm