0.3) Two poles PQ = 15 m and RS - 23 m stand on a ground as shown in the figure. If as - 15 m, then PR is equal to: 1) 13 m 2) 15m 3717m 4 18m 04) .... upto Rs are in AP. with common difference d, then a), 24, 2), da
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Given : Two poles PQ = 15 m and RS - 23 m stand on a ground
QS = 15 m
To Find : PR
Solution:
Draw QT || PR T is point on RS
QT = PR and RT = PQ = 15 m
ST = RS - RT = 23 - 15 = 8 m
in ΔQTS
QS² = QT² + ST²
=> 15² = QT² + 8²
=> QT² = 161
=> QT = 12.69 m
=> PR = 12.69 m
None of the given option matches
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