Question

0.30 g of a substance gives 0.88 g of carbon dioxide and 0.54 g of water calculate the percentage of carbon and hydrogen in it​

Answer 1

Answer:

Explanation:

Then it should be gaseous hydrocarbon

Apply poac for c

Which is

Xmoles cxhy=moles of co2

Apply poac for h

Y moles cxhy =2 moles of water

Divide equations

X/Y = moles of co2 / moles of h2o

X/Y=0.02/0.06

X/Y=2/6

And by limiting ratio concept

Limiting ratio = moles/coefficient

Limiting ratio = 0.3 / 12x+y

Carbon dioxide formed will be x times limiting ratio

0.3x / 12x+y = 0.02

0.3x=0.24x+0.02y

0.06x=0.02y

x/y=2/6

So gaseous hydrocarbon is ethane

So percentage of h = 6/30×100

=20

Percentage of c = 80