0.302g of organic compound gave 0.268g of silver bromide the percentage of bromine in the sanple is
Answers
Answered by
6
%of bromide = 0.268/0.302 x 100 = 88.741%
Answered by
10
Answer:
Explanation:
80*mass of AgBr*100/185* mass of organic compound
80*0.268*100/185*0.302
=38
Similar questions
Physics,
7 months ago
English,
7 months ago
Social Sciences,
7 months ago
Math,
1 year ago
Social Sciences,
1 year ago