0.30g of an organic compound containing C,H,O on combustion yeild ed 0.44g CO2 and 0.18g H2O .if 1 mole of compound weight 60g then molecular formula of the compound is
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Explanation:
Moles of C= moles of CO2=440.44=0.01 moles
Moles of H=2×moles of H2O=2×180.18=0.02 moles
Weight of oxygen = ( 0.30 - weight of carbon and hydrogen ) = (0.3−0.01×12−0.02×1)=0.16 gm
Moles of O=160.16=0.01 moles
Empirical formula =CH2O
Empirical formula mass =30 gm
n=3060=2
Formula=(CH2O)n=C2H4O2
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