0.31 g camphor (Molar mass 154.3) when added to 20g chloroform raised the boiling point of the solvent by 0.399 K. Calculate molar elevation constant of chloroform.
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Answer:
K
b
=3.88
o
C/m
W
Camphor
=0.3 g & Wt
Chloroform
=25.2
ΔT
b
=0.299
o
C
Now.
ΔT
b
=K
b
m
0.299=3.88×
M.W
Camphor
×25.2
0.3
×1000
M.W
Camphor
=
0.299×25.2
3.88×300
=154.5 g
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