Math, asked by sudippawar801, 4 months ago

0.31 The probability of a leap year
selected at random contain 53
Sunday is
a) 53/365
b) 52/366
O c) 2/7
O
d d) 1/7​

Answers

Answered by jaspreet1bains
1

Answer:

The two odd days can be {Sunday,Monday},{Monday,Tuesday},{Tuesday,Wednesday}, Wednesday,Thursday},{Thursday,Friday},{Friday,Saturday},{Saturday,Sunday}.

So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is

2/7

Answered by shivamchaudhary21
1

Answer:

So there are 7 possibilities out of which 2 have a Sunday. So the probability of 53 Sundays in a leap year is72.

Step-by-step explanation:

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