Question

0.35 moles of N2 into STP

Answer 1

0.35 × 28 = 9.8g of N2

so now just multiply these moles with 22.4L to get its volume at STP

so
22.4 × 0.35 = 7.84 L

Answer 2

There are two ways to calculate this if we assume STP of 1 atm and 273 K for the pressure and temperature.

We can use the Ideal Gas Law equations PV = nRT
P = 1 atm
V = ???
n = 0.355 moles
R = 0.0821 atmLmolK
T = 273 K

PV=nRT can be V=nRTP

V=(0.355mol)(0.0821atmLmolK)(273K) / 1atm

#V = 7.96 L

The second method is to us Avogadro's Volume at STP 22.4L=1mol

0.355mol×22.4L1mol=7.95L
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