Chemistry, asked by sowmya7192, 8 months ago

0.35mole of electrons were passed through two electrolyte solutions connected in series. If the solutions are of Ag+ and Cu^2+ Then
1. Amount of Ag deposits is 37.8 g
2. Amount of Cu deposits is 11.1 g
3. Amount of Ag deposits is 22.98 g
4. Amount of Cu deposits is 37.8 g​

Answers

Answered by Anonymous
1

Answer:

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Answered by pinkypearl301
0

Answer:

37.8g(option 1)

Explanation:

Given: 0.35mole of electrons were passed through two electrolyte solutions connected in series. If the solutions are of Ag+ and Cu^2+ Then

1. Amount of Ag deposits is 37.8 g

2. Amount of Cu deposits is 11.1 g

3. Amount of Ag deposits is 22.98 g

4. Amount of Cu deposits is 37.8 g​

1e- + Ag+ = Ag(s).

1mole e- deposits 1 mole Ag(s).

Therefore, 0.35mole electrons deposit= 0.35 mole Ag.

1 mol of Ag = 107.8g

Therefore, 0.35 mol of Ag= 107.8*0.35=37.73g.

Option 1 is correct.

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