Question

0.36 gram of triatomic gas x3 occupied 168 ml at one atm and 273 Kelvin. the atomic wight of x is
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Answer 1

Answer:

Molar volume at stp=22400 ml

Moles =168/22400=0.0075

or,wt/M=0.0075

or,M=0.36/0.0075

M=48

At wt=48/3=16

Answer 2

Hey Dear,

◆ Answer -

Atomic mass = 160 g/mol

◆ Explaination -

# Given -

W = 0.36 g

V = 168 ml = 0.168 L

T = 273 K

P = 1 atm

# Solution -

Applying ideal gas eqn,

PV = nRT

PV = (W/M)RT

M = WRT/PV

M = (0.36 × 0.821 × 273) / (1 × 0.168)

M = 480 g/mol

Atomic mass of X will be 1/3rd of molar mass of X3.

Atomic mass = 1/3 × 480

Atomic mass = 160 g/mol

Therefore, atomic weight of X is 160 g/mol.

Thanks dear...