Question

0.36 part of a stick is dipped in water . if the remaining length 9f the stick 8d 450.72 cm what us the whole lenght of the stick ?

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Answer 1

Given

Dipped part of stick in water =0.45

Remaining length =450.78

Let whole length =1

Then

Remaining =1-0.43

=0.57

But according to the question it is 450.78cm

Comparing both quantities

Then value of 1 unit = 450.78/0.57


=790.84 cm

So length of whole stick is =790.84


Another way to solve it

Let change the 0.43 in fraction form

=43/100

Now the part Dipped =43

And whole=100

Then remaining =100-43=57

But according to the question it is 450.78cm

So 1 unit assumed =450.78/57

=7. 9084

For whole length =100x value of 1 unit

=100x7.9084

=790.84cm

Answer 2

Answer:

Dipped part of stick in water =0.45

Remaining length =450.78

Let whole length =1

Then

Remaining =1-0.43

=0.57

But according to the question it is 450.78cm

Comparing both quantities

Then value of 1 unit = 450.78/0.57

=790.84 cm

So length of whole stick is =790.84

Another way to solve it

Let change the 0.43 in fraction form

=43/100

Now the part Dipped =43

And whole=100

Then remaining =100-43=57

But according to the question it is 450.78cm

So 1 unit assumed =450.78/57

=7. 9084

For whole length =100x value of 1 unit

=100x7.9084

=790.84cm