0.365 gm of hcl was dissolved in 4 litres of water.find the pH of solution
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Number of moles in 0.365 grams of HCl = given mass /molar mass
= 0.365/36.5
= 0.01 moles
These 0.01 moles of HCl are present in 1 litre.
So, the concentration of H⁺ = 0.01 moles/litre = 10⁻² moles/litre
pH = -log[H⁺] = -log[10⁻²] = 2
Thus, the pH of o.365 grams of HCl present in 1 litre of solvent is 2.
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