Question

0.365g of an organic compound containing nitrogen gave 56ml of nitrogen at STP . The percentage of nitrogen in the given compound is

Answer 1

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Moles of nitrogen =56/22400

mass of nitrogen in sample

=28∗56/22400=0.07gm

so, no. of N =0.07∗100/0.365 = 19.18

Nearest integer is 19.