English, asked by VasterPart, 9 months ago

0.36g of an organic compound containing sulphur produced H2SO4 by Carius method, which on treatment with BaCl2 produced quantitatively 0.2330g of BaSO4. Calculate the percentage of S in the compound..??

Answers

Answered by MastVibhu
47

Answer:

8.89%

Explanation:

Moles of S in BaSO4 = 1 * Mole of BaSO4

                                   = 0.2330/233 = 0.001

Weight of S = 0.001 * 32 g = 0.032g

Percentage of S = 0.032/0.36 * 100 = 8.89%.

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Answered by llxdevilgirlxll
5

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