Question

0.36g of each aluminum and oxygen produces alumina.Which of the following is limiting reactant?

Answer 1

Explanation:

as oxygen is taken in excess so we will not consider its moles we will take on the moles of aluminium and find the moles of product by this method 4 moles of Al gives moles of Al2O3 =2 1mole will give =2/4 0.36 will give =2/4x0.36=0.18 to do so we will form an equation first 4Al +3o2 ( after reaction )2Al2o3

Answer 2

Answer:

0.18 moles

Explanation:

For all these kinds of questions, write a balanced chemical formula first.

Step: 1

The following apply to the reaction equations above.

$4Al + 3O_2$ → $2Al_2O_3$

Step: 2

Now, to know the limiting reactants, find the number of moles of product produced by each reactant.  

4 mol Al gives $Al_2O_3 = 2 mol$

1 mol of Al gives $Al_2O_3 = \frac{2}{4} = 0.5 mol.$

3 mol $O_2$ gives $Al_2O_3 = 2 mol$

1 mol to $Al_2O_3 = \frac{2}{3} mol = 0.67 mol$

Step : 3

Al is the limiting reactant as it produces the least amount of product.

1 mol of Al gives $Al_2O_3 = \frac{2}{4} = 0.5 mol.$

0.36 mol Al gives $Al_2O_3 = \frac{2}{4}=$$0.5$×$0.36 mole=0.18 moles$

Hence, the correct answer is 0.18 moles

Write chemical reactions for sodium to react with carbon dioxide to form sodium carbonate

https://brainly.in/question/5682993?referrer=searchResults

Salts formed when sodium hydroxide reacts with carbonic acid​

https://brainly.in/question/8276639?referrer=searchResults

#SPJ2