0.36moles of each aluminium and oxygen react with each other to produce aluminium oxide .the amount of product is . . ?. . a) 0.18mol b)0.27mol c)0.24mol d)0.09mol
Answers
Answer:
option a is answer.
Explanation:
For all such type of questions write the balanced chemical equation first of all.
For the above reaction equation is :
4Al + 3O2 -- > 2Al2O3
Now find the number of moles of product being produced by each reactant in order to know the limiting reactant.
4 mole of Al produces Al2O3 = 2 moles
1 mole of Al produces Al2O3 = 2/4 = 0.5 mole
3 mole of O2 produces Al2O3 = 2 moles
1 mole will produce Al2O3 = 2/3 moles = 0.67 moles
Since Al produces least amount of product , so it is the limiting reactant.
1 mole of Al produces Al2O3 = 2/4 = 0.5 mole
0.36 mole of Al produces Al2O3 = 2/4 = 0.5 x 0.36 mole = 0.18 moles
Concept:
In a chemical reaction, one or more substances—also known as reactants—are changed into one or more additional substances—also known as products. Chemical elements or chemical compounds make substances.
Given:
The number of moles of aluminum = 0.36 moles
The number of moles of oxygen = 0.36 moles
Find:
0.36 moles of each aluminum and oxygen react with each other to produce aluminum oxide. The amount of product is?
Solution:
First, write a balanced chemical equation of aluminum and oxygen.
4Al + 3O₂ → 2Al₂O₃
In order to identify the limiting reactant, determine the quantity of product being produced by each reactant.
Al₂O₃ = 2 moles from 4 moles of aluminum.
Al₂O₃ is produced when 1 mole of aluminum is divided by 4 to equal 0.5 moles.
Al₂O₃ = 2 moles when 3 moles of O₂ are used.
Al₂O₃ may be produced from 1 mole by using 2/3 moles, or 0.67 moles.
Al is the limiting reactant as it yields the least quantity of product.
Al₂O₃ is produced when 1 mole of aluminum is divided by 4 to equal 0.5 moles.
Al₂O₃ is produced = 2/4 = 0.5 x 0.36 mole
= 0.18 moles
Thus, 0.18 moles of Al₂O₃ are found in this reaction.
Hence, the correct option (a) 0.18 mol.
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