0.37q charge is stored on the capacitor, what will be the current at this point
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Answered by
1
Answer:
.63i
Explanation:
current at time t=ie^(-t/τ)
to find e^(-t/τ)
.37q=q(1-e^(-t/τ))
e^(-t/τ)=.63
therefore current=.63i
where I=V/R
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