0.390 g of an organic substance produced 04160 g of Baso, during Curta
estimation. Find the percentage of sulphur in it?
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Answer:
mass of organic compound = 0.751
mass of barium sulphate = 0.3184
molar mass barium sulphate = 233 gm
0,3184 barium sulphate containe =
233
32
×0.3184=0.043
percentage of sulpur =
0.751
0.043
×100
=5.8%
Explanation:
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