Question

(0.3p-0.4q)² ch9 std 8
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Answer 1

(0.4p−0.5q)  

2

 

Using,(a−b)  

2

=a  

2

−2ab+b  

2

 

=(0.4p)  

2

−2(0.4p)(0.5q)+(0.5q)  

2

 

=0.16p  

2

−0.4pq+0.25q  

2

Answer 2

• We have to evaluate the above expression by using the given data.

             Given data:- $(0.3 p-0.4 q)^{2}.$

             To find:- Value of the given expression.

             Solution:-

• We know that factorization means reducing any algebraic or quadratic equation.
• We know the identity

        $(a-b)^{2}=a^{2} -2ab+b^{2} .$

        Therefore we get,

         $(0.3 p-0.4 q)^{2}\\=(0.3p)^{2} -2(0.3p)(0.4q)+(0.4q)^{2} \\=0.09p^{2} -0.24pq+0.16q^{2} .$

Hence we will get the value $(0.3 p-0.4 q)^{2}=0.09p^{2} -0.24pq+0.16q^{2} .$