Question

0.3y2 + 0-4y - 1.5=0 solve the following by factorising

Answer 1

$\huge\underline\mathfrak\red{Answer}$

$0.3 {y}^{2} + 0.4y - 1.5 = 0 \\ \\ 0.3 {y}^{2} + 0.9y - 0.5y - 1.5 = 0 \\ \\ 0.3y(y + 3) - 0.5(y + 3) = 0 \\ \\ (y + 3)(0.3y - 0.5) = 0 \\ \\ from \: this \: we \: get \\ \\ y + 3 = 0 \\ first \: solution \\ y = - 3 \\ \\ and \\ \\ 0.3y - 0.5 = 0 \\ \\ y = \frac{0.5}{0.3} \\ \\ second \: solution \\ \\ y = \frac{5}{3}$

Answer 2

Answer:

(y +0.3) ( 0.3y - 0.5)

Step-by-step explanation:

Given

0.3y² +0.4y -1.5

factorise this we get

0.3y² +0.9y - 0.5y- 1.5

taking common

0.3y (y +3) -0.5 (y +3)

(y +3) ( 0.3y - 0.5)