0.4 I cap + 0.8jcap + c kcap represent a unit vector when c is
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Unit Vector {A(cap)} = 0.4 i(cap) + 0.8 j(cap) + c k(cap)
Because the magnitude of a unit vector is 1, so
√{ (0.4)^2 + (0.8)^2 + (c)^2 } = 1
0.16 + 0.64 + c^2 = 1
0.80 + c^2 = 1
c^2 = 1 - 0.80 = 0.20
c = √(0.2)..........●
Thus, the value of c is √(0.2)).
Hope it was helpful.
Because the magnitude of a unit vector is 1, so
√{ (0.4)^2 + (0.8)^2 + (c)^2 } = 1
0.16 + 0.64 + c^2 = 1
0.80 + c^2 = 1
c^2 = 1 - 0.80 = 0.20
c = √(0.2)..........●
Thus, the value of c is √(0.2)).
Hope it was helpful.
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