Question

0.4 I cap + 0.8jcap + c kcap represent a unit vector when c is

Answer 1

Unit Vector {A(cap)} = 0.4 i(cap) + 0.8 j(cap) + c k(cap)

Because the magnitude of a unit vector is 1, so

√{ (0.4)^2 + (0.8)^2 + (c)^2 } = 1

0.16 + 0.64 + c^2 = 1

0.80 + c^2 = 1

c^2 = 1 - 0.80 = 0.20

c = √(0.2)..........●

Thus, the value of c is √(0.2)).



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Answer 2

Explanation:

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