0.4 mole of HCl and 0.6 mole of MgCl2 were dissolved to have 400 mL of the solution. The molarity of CI- in the final solution is
Answers
The molarity of Cl⁻ in the final solution is 4M
Explanation:
HCl → H⁺ + Cl⁻
0.4 mole of HCl on disassociation will give 0.4 mole of H⁺ and 0.4 mole of Cl⁻ ions
MgCl₂ → Mg²⁺ + 2Cl⁻
0.6 moles of MgCl₂ will give 0.6 moles of Mg²⁺ and 1.2 moles of Cl⁻ ions
Total moles of Cl⁻ ions = 0.4 + 1.2 = 1.6 moles
Volume of solution = 400 mL = 0.4 Litre
Therefore, molarity of Cl⁻ in the final solution
= Moles of solute/Volume of solution in Litre
= 1.6/0.4
= 4
Therefore, molarity of Cl⁻ is 4M
Hope this answer is helpful.
Know More:
Q: 500 ml of 0.2 M AlCl3 is mixed with 500 ml of 0.1 M MgCl2 solution. Then molarity of Cl- in final solution is?
Click Here: https://brainly.in/question/387512
Q: 0.2 mol of HCl and 0.1 mol of barium chloride dissolved in water to produce a 500 mL solution.The molarity of Cl- is ?
Click Here: https://brainly.in/question/3428532