0.4. Observe the figure given and answer the questions given below. The path of a body is shown. (1) Calculate the total distance travelled and (2) Total displacement of a body from A to B. A starting point B end point A 4m 2 m 4 m 2m 4m 2.5 m 3m 2m 4m 2m 3m B.
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Answer:
1. Distance = Length of path travelled
=AB+BC
=15+9
=24km
Displacement = Shortest path from initial to final position
=AC
=(AB)2+(BC)2{Pythagoras Theorem}
=225+81
=17.5km
Since, F = constant, we can use.
W=F∙S
2. Here, S=rf−ri=(i^+2j^+3k^)−(2i^+3j^+4k^)
=(−i^−j^−k^)
∴W=(2i^+3j^+4k^)∙(−i^−j^−k^)
=−2−3−4=−9J
Explanation:
hope it's helpful
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