Question

0.40 g of an organic compound gave 0.3 g of silver bromide of Carius
method. Find the percentage of bromine in the compound. [Atomic mass
of Ag & Br are 105 and 80 u]

Answer 1

Answer:

Explanation:31.91 answer

Answer 2

The percentage of bromine in the compound is 32.43%.

Explanation:

Percentage of halogen in a compound by the help of Carius method :

$\% (halogen)=\frac{\text{given mass of AgX}\times \text{atomic mass of X}\times 100}{\text{Molecularar mass of AgX}\times \text{Mass of organic compound}}$

We have:

Weight of silver bromide = 0.40 g

Atomic mass of bromide ion = 80 u = 80 g/mol

Molecular mass of AgBr = 105 u + 80 u = 185 u = 185 g/mol

Weight AgX obtained = 0.30 g

$\%(bromine)=\frac{0.30 g\times 80 g/mol\times 100}{185 g/mol\times 0.40 g}$

=  32.43%

The percentage of bromine in the compound is 32.43%.

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