0.43 part of a stick is dipped in water. If the remaining length of the stick is 450.78 cm,what is the whole length of the stick? please write full statement
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Given
Dipped part of stick in water =0.45
Remaining length =450.78
Let whole length =1
Then
Remaining =1-0.43
=0.57
But according to the question it is 450.78cm
Comparing both quantities
Then value of 1 unit = 450.78/0.57
=790.84 cm
So length of whole stick is =790.84
Another way to solve it
Let change the 0.43 in fraction form
=43/100
Now the part Dipped =43
And whole=100
Then remaining =100-43=57
But according to the question it is 450.78cm
So 1 unit assumed =450.78/57
=7. 9084
For whole length =100x value of 1 unit
=100x7.9084
=790.84cm
This is ur ans hope it will help you in case of any doubt comment below
Dipped part of stick in water =0.45
Remaining length =450.78
Let whole length =1
Then
Remaining =1-0.43
=0.57
But according to the question it is 450.78cm
Comparing both quantities
Then value of 1 unit = 450.78/0.57
=790.84 cm
So length of whole stick is =790.84
Another way to solve it
Let change the 0.43 in fraction form
=43/100
Now the part Dipped =43
And whole=100
Then remaining =100-43=57
But according to the question it is 450.78cm
So 1 unit assumed =450.78/57
=7. 9084
For whole length =100x value of 1 unit
=100x7.9084
=790.84cm
This is ur ans hope it will help you in case of any doubt comment below
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