Chemistry, asked by meetk6365, 1 year ago

0.456 g of a metal gives 0.606 g of its chloride. Calculate the equivalent mass of the metal.

Answers

Answered by JinKazama1
75
Final Answer : Equivalent Mass of Metal : 107.92g

Steps and Understanding :
1) Let the metal be M such that
M + 1/2 Cl2 ------> MCl
as shown in pic.

Mass of M = 0.456g
Mass of MCl = 0.606g

2) Let the Molecular mass of Metal M be (x) .

Now, By reaction
No. of moles of M = No. of moles of MCl
 =  >  \frac{0.456}{x}  =  \frac{0.606}{x + 35.5}  \\  =  >  \frac{x + 35.5}{x}  =  \frac{0.606}{0.456}  \\  =  > x = 35.5 \times  \frac{0.456}{0.150}  \\  =  > x = 107.92 \: g

3) No. of electrons loses by M in reaction is 1 .
So, Equivalent mass of M is
107.92 / 1
= 107.92 g
Attachments:

mericbalak: thank you very much!
Answered by tiwaavi
76
Let the Symbol of the Metal be M.

Mass of the Metal = 0.456 g.
Mass of the Metallic Chloride = 0.606 g.

Reaction for the Formation of the Metallic Chloride is given below,

 2M + Cl₂ ------ 2MCl.

From this Reaction, 
2 mole of the Metals forms two moles of the Metallic Chloride.

Now, Let the molar mass of the Metal be m.
∴ No. of moles of Metal = Mass/Molar mass.
   = 0.456/m

Similarly, No. of mole of Metallic Chloride = Mass/Molar Mass.
Molar mass of the Metallic Chloride = Molar mass of (Metal + Chlorine)
 ∴ No. of moles of Metallic Chloride = (m + 35.5)
  = 0.606/(m + 35.5)

Since, the number of moles of the metal and the chloride are equal,
∴ 0.456/m = 0.606/(m + 35.5)
∴ 0.456(m + 35.5) = 0.606m
∴ 0.456m + 16.188 = 0.606m
⇒ 0.606m - 0.456m = 16.188
⇒ m = 16.188/0.15
⇒ m = 107.92 g.

Since, the number of the Electrons lost by the Metal is (From the Reaction) , therefore, molar mass will be equal to the Equivalent mass of the metal.

∴ Equivalent mass of the metal is 107.92 g.



Hope it helps.

mericbalak: thank you!
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