Question

0.45g of acid (m.w=90)was exactly neutralised by 20ml of 0.5N NaOH find valency factor of acid​

Answer 1

Answer:

Let the n  

factor

​  

 be n.

Moles of acid =  

90

0.45

​  

=5 milimoles

Comparing equivalents of acid and NaOH

5×n=0.5×20

n=2

For acid, n  

factor

​  

=basicity

∴ Basicity is 2