Question

0.45N and 0.6N NaOH solution are mixed in 2:1 ratio by volume. The amount of solute present in one litre of this solution is

Answer 1

0.45 N & 0.6 N NaOH solution are mixed in by volume. The amount of solute present in 1 lit of this solution is. a) 0.5 gm.

Answer 2

Answer: 20g

Explanation:

From the normality equation:

$N_{1}V_{1}+N_{2}V_{2}=N_{final}\times V_{final}\\\\Let\ us\ assume\ the\ volume\ of\ 0.45N\ NaOH\ is\ 2x\ and\ the\ volume\ of\ 0.6N\ NaOH\ is\ x:\\Then, \\0.45\times 2x+0.6\times x=N_{final}\times 3x\\\\N_{final}=(0.9x+0.6x)/3x=0.5N\\V_{final}=1\ litre\\\\N=No.\ of\ gram\ equivalents/Volume\ of\ solution\ in\ litres\\0.5=No.\ of\ gram\ equivalents/1=Weight/Equivalent\ weight\\Equivalent\ weight\ of\ NaOH=Molecular\ weight/n\ factor=40/1=40\\0.5=W/40\\\\W=0.5\times 40=20g$

The amount of solute (NaOH) present in 1 litre of the solution is 20g.