Question

0.4i + 0.8j + ck represent a unit vector then value of c is

Answer 1

thats your answer check it

Answer 2

VALUE OF c is 0.44

Given:

0.4i + 0.8j + ck represent a unit vector.

To find:

Value of c ?

Calculation:

When a vector is unit vector, the magnitude of the vector will be 1 .

So, we can say:

$\sqrt{ {(0.4)}^{2} + {(0.8)}^{2} + {c}^{2} } = 1$

$\implies {(0.4)}^{2} + {(0.8)}^{2} + {c}^{2} = {1}^{2}$

$\implies 0.16+ 0.64 + {c}^{2} = {1}^{2}$

$\implies 0.8+ {c}^{2} =1$

$\implies {c}^{2} =0.2$

$\implies c = \sqrt{0.2}$

$\implies c =0.44$

So, value of c is 0.44