0.4x +0.3y=1.7 and 0.7x-0.2y=0.8 by elimination method
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Answered by
307
as/q
0.4x + 0.3y=1.7...(1)
0.7x - 0.2y= 0.8...(2)
multiplying eq 1 by 2 & eq 2 by 3, we get
0.8x + 0.6y = 3.4..(3)
2.1x - 0.6y = 2.4..(4) now adding eq 3&4
2.9x= 5.8
x=5.8/2.9
x=2
putting the value of x in eq (1)
0.4×2 + 0.3y=1.7
0.3y= 1.7-0.8
y=0.9/0.3
y=3
Answer x=2 y=3
0.4x + 0.3y=1.7...(1)
0.7x - 0.2y= 0.8...(2)
multiplying eq 1 by 2 & eq 2 by 3, we get
0.8x + 0.6y = 3.4..(3)
2.1x - 0.6y = 2.4..(4) now adding eq 3&4
2.9x= 5.8
x=5.8/2.9
x=2
putting the value of x in eq (1)
0.4×2 + 0.3y=1.7
0.3y= 1.7-0.8
y=0.9/0.3
y=3
Answer x=2 y=3
Answered by
4
Answer:
When we solve the equation and by the elimination method we get x = 2 & y = 3.
Step-by-step explanation:
We have two equations as
.....(1)and
....(2)
and it is asked to solve for x and y by elimination method which can be done as
Step 1 of 3
Multiply the eq(1) with 2 and eq(2) by 3 we get
0.8x + 0.6y = 3.4 ....(3)
2.1x -0.6y = 2.4 ....(4)
Step 2 of 3
Now by adding eq(3) and eq(4) we get
2.9x = 5.8
⇒x = 5.8/2.9
⇒ x = 2
Step 3 of 3
Now by putting the value of x in eq(1) we get
0.4*2 + 0.3y = 1.7
⇒0.3y = 1.7 - 0.8
⇒0.3y = 0.9
⇒ y = 3
Hence by solving the given equations by elimination method we get the values of x and y as 2 & 3 respectively.
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