Question

0.4x-0.5/0.3x+0.2=2/5​

Answer 1

Answer:

$0.4x {}^{2} - \frac{0.5}{0.3} x + 0.2 = \frac{2}{5} \\ \frac{4}{10}x {}^{2} - \frac{5}{3} x + \frac{2}{10} = \frac{2}{5} \\ \frac{2}{5}x {}^{2} - \frac{5}{3} x + \frac{1}{5} = \frac{2}{5} \\ 2 x{}^{2} - \frac{25}{3} x + 1 = 2 \\ 6x {}^{2} - 25x + 3 = 6 \\ 6x {}^{2} - 25x - 3 = 0 \\ \\ here \: find \: the \: roots \: of \: this \: equation \: from \: there \: you \: will \: get \: \\ your \: answer \: if \: the \: question \: is \: like \: this \: \\ \\ otherwise \\ \\ 0.4x - \frac{0.5}{0.3} x + 0.2 = \frac{2}{5} \\ \frac{2}{5} x - \frac{5}{3} x + \frac{1}{5} = \frac{2}{5} \\ \frac{ - 19}{15} x = \frac{2}{5} - \frac{1}{5} \\ x = \frac{1}{5} \times ( - \frac{15}{19} ) = \frac{ - 3}{19} \\ \\ thus \: x \: is \: equal \: to \: - \frac{3}{19} .$