0.5+0.7=0.74 0.3+0.5=0.5
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0.5 x +0.7 y = 0.74 (i)
multiply 10 on both sides in (i)
=> 5x+7y=7.4
0.3 x + 0.5 y =0.5 (ii)
multiply 10 on both sides in (ii)
3 x + 5 y = 5
y=1-0.6x (from ii equation)
Now, Substitute value in equation i
5x+7y = 5x + 7(1-0.6x)=7.4
=>5x +7-4.2x =7.4
=>0.8x+ 7 = 7.4
=>x=0.5
Now substitute x value in any equation.
Let us take the second equation.
0.3x + 0.5y =0.5
(0.3×0.5)+0.5y= 0.5
0.3+y= 1
∴y=0.7
Hope my answer is helpful to u. Pls mark it the brainliest if u like.
multiply 10 on both sides in (i)
=> 5x+7y=7.4
0.3 x + 0.5 y =0.5 (ii)
multiply 10 on both sides in (ii)
3 x + 5 y = 5
y=1-0.6x (from ii equation)
Now, Substitute value in equation i
5x+7y = 5x + 7(1-0.6x)=7.4
=>5x +7-4.2x =7.4
=>0.8x+ 7 = 7.4
=>x=0.5
Now substitute x value in any equation.
Let us take the second equation.
0.3x + 0.5y =0.5
(0.3×0.5)+0.5y= 0.5
0.3+y= 1
∴y=0.7
Hope my answer is helpful to u. Pls mark it the brainliest if u like.
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