Math, asked by hasan95hey, 1 year ago

{0.5^4 - 0.4^4}/{0.5^2 + 0.4^2} is?

Answers

Answered by khushipar
19
Hope it helps.... :)
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Answered by TooFree
13

\dfrac{0.5^4 - 0.4^4}{0.5^2 + 0.4^2} = \dfrac{(0.5^2)^2 - (0.4^2)^2}{0.5^2 + 0.4^2}


Write it as the difference between two perfect square:

\dfrac{0.5^4 - 0.4^4}{0.5^2 + 0.4^2}= \dfrac{(0.5^2 + 0.4^2)(0.5^2 - 0.4^2)}{0.5^2 + 0.4^2}


Cancel out common factors:

\dfrac{0.5^4 - 0.4^4}{0.5^2 + 0.4^2}= 0.5^2 - 0.4^2


Evaluate each exponents:

\dfrac{0.5^4 - 0.4^4}{0.5^2 + 0.4^2}=0.25 - 0.16


Subtract:

\dfrac{0.5^4 - 0.4^4}{0.5^2 + 0.4^2} =0.09

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