0.5(70 + 4) = 7 - 1.5d
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Answer:
Ribosomes are membranous structure present on the endoplasmic reticulum.
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Answer:
0.5(70+4)=7-1.5d
0.5(74)=7-1.5d
37=7-1.5d
-1.5d=37-7=30
-1.5d=30
d=-30/1.5
d=-20
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