Math, asked by ankulkumar887366, 6 months ago

0.5(70 + 4) = 7 - 1.5d​

Answers

Answered by Anonymous
1

Answer:

Ribosomes are membranous structure present on the endoplasmic reticulum.

Answered by Anonymous
2

Answer:

0.5(70+4)=7-1.5d

0.5(74)=7-1.5d

37=7-1.5d

-1.5d=37-7=30

-1.5d=30

d=-30/1.5

d=-20

Step-by-step explanation:

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