Question

0.5 farady of electricity is passed through CaCl2, the amount of calcium metal deposited on electrode is? A) 10g
B) 20g
C)30g
D)40g

Answer 1

ANSWER

Ca

2+

+2e

−

→Ca

Number of moles of Ca=

40g/mol

10g

=0.25mol

1 mole Ca requires =2 moles of electrons =2 faradays of electricity.

0.25 mole Ca=2×0.25=0.50 moles of electrons =0.5 faradays of electricity.

Hence, 0.5 Faradays of electricity are required to deposit 10 g of calcium from molten calcium chloride using inert electrodes