Question

0.5 g of an oxalate sample (C_2O_4 + impurities ) is dissolved in water and diluted up to 100 ml. 10 ml of this solution is completely oxidized with 15 ml N/2 KMnO_4. Calculate % purity of of the sample.
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Answer 1

Answer:

i think it should be 5 g

Explanation:

10 ml = 7.5

100 ml = 75

equivalent = 75

moles*f*1000=75

moles*2000=75

moles=75/2000

moles=0.0375

w/88=0.0375

w=3.3

percentage purity = 3.3/5*100

=66