Question

0.5 gm of zinc dissolved in dilute sulphuric acid gives 183 cc of moist hydrogen at 9 degrees * C and 748 mm. What would be the volume of the gas at NTP? Calculate the weight of Zinc required to liberate 22.4 L of dry hydrogen at NTP? (Aq. Tension at 9^ C=8.6mm)
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Answer 1

Answer:

Let us consider the problem.

zinc reacts with sulfuric acid according to the following formula.

Zn+H

2

SO

4

→ZnSO

4

+H

2

Therefore, 1 mole of zinc reacts to give 1 mole of hydrogen

Volume of 1 mole of hydrogen at STP is 22400 ml

1 mole of Zn is 65 grams

Therefore 0.65 grams of zinc reacts to give 224 ml of hydrogen.