Question

0.5 gr. oxalate was dissolved in water
and solution made to 100 ml. on titration 10ml of of this solution required 15 ml of
N/20kmno4. Caluculate the Percentage of oxalate
in the Sample ?​

Answer 1

Answer:

Percentage of oxalate ions in salt = 66 %

Explanation:

When oxalate salt is dissolved in water -

(C2O4)-- → 2CO2 + 2e-

Let x be weight of oxalate ions in salt.

As solution is completely oxidized with KMnO4,

Meq(Oxalate) = Meq(KMnO4)

x / (88/2) × 1000 = 90 × 1/20

x = 44 × 90 / (1000×20)

x = 0.198 g

Therefore, percentage of oxalate ions in salt

= 0.198 / 0.3 × 100

= 66 %

Answer 2

Answer:

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